12mn-4m(m^2-3n+1)
来源:学生作业帮 编辑:神马作文网作业帮 分类:数学作业 时间:2024/11/12 02:40:15
12mn-4m(m^2-3n+1)
9(x+2)(x-2)-(3x-2)^2
(x-3y+2)(x+3y+2)
[(x+y)^2-(x-y)^2+4xy]/(-2x),其中x=-2 y=1/2
解方程 2(2x-1)^2-8(x-1)(3+x)=34
9(x+2)(x-2)-(3x-2)^2
(x-3y+2)(x+3y+2)
[(x+y)^2-(x-y)^2+4xy]/(-2x),其中x=-2 y=1/2
解方程 2(2x-1)^2-8(x-1)(3+x)=34
第一题:12mn-4m(m^2-3n+1)
=12mn-4m^3+12mn-4m
=-4m^3+24mn-4m
=-4m(m^2-6mn+1)
第二题:9(x+2)(x-2)-(3x-2)^2
=9(x^2-4)-(9x^2-12x+4)
=9x^2-36-9x^2+12x-4
=12x-40
第三题:(x-3y+2)(x+3y+2)
=(x+2-3y)(x+2+3y)
=(x+2)^2-9y^2
=x^2-9y^2+4x+4
第四题: [(x+y)^2-(x-y)^2+4xy]/(-2x), 其中x=-2 y=1/2
=[(x^2+2xy+y^2)-(x^2-2xy+y^2)+4xy]/(-2x)
=8xy/(-2x)
=-4y
=-2
第五题:2(2x-1)^2-8(x-1)(3+x)=34
(4x^2-4x+1)-4(x^2+2x-3)=17
-12x+13=17
-12x=4
x=-1/3
=12mn-4m^3+12mn-4m
=-4m^3+24mn-4m
=-4m(m^2-6mn+1)
第二题:9(x+2)(x-2)-(3x-2)^2
=9(x^2-4)-(9x^2-12x+4)
=9x^2-36-9x^2+12x-4
=12x-40
第三题:(x-3y+2)(x+3y+2)
=(x+2-3y)(x+2+3y)
=(x+2)^2-9y^2
=x^2-9y^2+4x+4
第四题: [(x+y)^2-(x-y)^2+4xy]/(-2x), 其中x=-2 y=1/2
=[(x^2+2xy+y^2)-(x^2-2xy+y^2)+4xy]/(-2x)
=8xy/(-2x)
=-4y
=-2
第五题:2(2x-1)^2-8(x-1)(3+x)=34
(4x^2-4x+1)-4(x^2+2x-3)=17
-12x+13=17
-12x=4
x=-1/3
若m-n=4,mn=-1求(9-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)
若m-n=4,mn=-1,求(-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)的值
已知m-n=3,mn=-1,求多项式-2mn+2m+3n-3mn-2n+2m-4n-m-mn的值
已知m-n=2,mn=1,求多项式(2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)的值
已知|m-n-2|与(mn-1)^互为相反数,求(-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)的值
若m-n=4,mn=-1,求(-2mn+m+n)-(3mn+5n-5m)-(m+4n-3mn)的值
3(m^2-mn+2n^2)-2(mn-m^2+n^2)+(5mn-4n^2+1)
知m*m-mn=1,4mn-3n*n=-2,则m*m+3mn-3n*n的值是多少
3(m^2n+mn)-4(mn-2m^2n)+mn.
(4mn²+3m²n-4m)-2(mn²+3/2m²n+1)化简
计算(-2mn)^3(mn+1/2)(m^2n^2-1/2mn+1/4)
已知m-n=4,mn=2,求多项式(-2mn+2m+3n)-(3mn+2n-2m)-(m+4n+mn)的值.