int a=5 double d=12345.6789 printf("%*.*lf\n",a+5,a-3,d) 请问答

C语言 int a;int b; }d[3] ={{1,4},{2,5},{6,7}}; printf("%d\n",d { int a[]={1,2,3,4,5,6}; int*p; p=a; printf("%d\n",*p); prin int a=10;f1(){int a=20;printf("%d",a);}f2(){printf("%d",a);} main() {int a[10]={1,2,3,4,5}; printf("%d\n",a[6]);}输出的结果是啥, #include main() { int a=5,b=4,c=3,d; d=(a>b>c); printf("%d\n Int a=1; Int *p; p=&a; printf(“%d\n”,*p); 和Int a=1; Int*p; * 以下程序的输出结果是 int a=5,b=4,c=6,d; printf("%d\n",d=a>b?(a>c?a:c)b int a=5;printf ("%%d",a);输出的为什么是%d呀具体点, main() { int a=5,b=4,x,y; x=a++*a++*a++; printf(“a=%d,x=%d\n void main( ) { int a=5,b=8; printf(“a=%d b=%d\n”,a,b) ; a=a+ main( ) {unsigned int a=3,b=10; printf("%d/n",a1); } #include main() {unsigned int a=65535; printf("a=%d\n",a); }