10y+x/10x+y=5/6
已知x,y满足约束条件{2x+5y>=10,2x-3y>=-6,2x+y
3x+2y=6 ,5x+6y=10那么x+y=?
已知X,Y,满足(X+3Y)(X-3Y)=-10(Y^2-6/5)和2X(Y-1)+4(1/2X-1)=0
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai
2X+Y+Z=10,X+2Y+Z=-6,X+Y+2Z=8 5X+4Y-3Y=13,2X-3Y+7Z=19,3X-Y=2X
化简(x+y)-(2x+y/2)-(3x+y/6)-(4x+y/12)-(5x+y/20)-……-(10x+y/90)
已知4x+y-4x-6y+10=0,求(三分之二x√9x+y√y分之x)-x√x分之1-5x√x分之y)的值
(7x-10y)-(-10y-5x)=?
x+y=6 10x+y≤42
用加减法解方程组:{(x+y)/6+(x-y)/10=3 (x+y)/6+(y-x)/10=-1
解方程组x+y/6+x-y/10=3,x+y/6+y-x/10=-1
解方程组 10(x-y)=3(x+y)+15 6(x+y)=4(2x-y)+16