x³-3x²+4用拆项法分解因式
来源:学生作业帮 编辑:神马作文网作业帮 分类:数学作业 时间:2024/11/14 20:55:40
x³-3x²+4用拆项法分解因式
/>拆法一:
原式=x³+x²-4x²+4
=x²﹙x+1﹚-4﹙x+1﹚﹙x-1﹚
=﹙x+1﹚﹙x²-4x+4﹚
=﹙x+1﹚﹙x-2﹚²
拆法二:
原式=x³+1-3x²+3
=﹙x+1﹚﹙x²-x+1﹚-3﹙x+1﹚﹙x-1﹚
=﹙x+1﹚﹙x²-x+1-3x+3﹚
=﹙x+1﹚﹙x-2﹚²
拆法三:
原式=4x³-3x³-3x²+4
=4﹙x³+1﹚-3x²﹙x+1﹚
=4﹙x+1﹚﹙x²-x+1﹚-3x²﹙x+1﹚
=﹙x+1﹚[4﹙x²-x+1﹚-3x²]
=﹙x+1﹚﹙x-2﹚²
原式=x³+x²-4x²+4
=x²﹙x+1﹚-4﹙x+1﹚﹙x-1﹚
=﹙x+1﹚﹙x²-4x+4﹚
=﹙x+1﹚﹙x-2﹚²
拆法二:
原式=x³+1-3x²+3
=﹙x+1﹚﹙x²-x+1﹚-3﹙x+1﹚﹙x-1﹚
=﹙x+1﹚﹙x²-x+1-3x+3﹚
=﹙x+1﹚﹙x-2﹚²
拆法三:
原式=4x³-3x³-3x²+4
=4﹙x³+1﹚-3x²﹙x+1﹚
=4﹙x+1﹚﹙x²-x+1﹚-3x²﹙x+1﹚
=﹙x+1﹚[4﹙x²-x+1﹚-3x²]
=﹙x+1﹚﹙x-2﹚²