若有:int a=10,s=0; while(a!=0) {a--; s+=--a;} 则a= s=

int a=2; int f(int a); {return (a)++;} main() {int s=0; {int int f(int n); main() { int a=3,s; s=f(a); s=s+f(a); printf(" int f(int n); main() { int a=3,s; s=f(a); s=s+f(a); printf(& main() { int a,s,max; scanf("%d%d",&a,&s); if(a>s) { max=a } m=(int)(s[i]-'a')是什么意思 struct st{int x,int*y;}*p; int s[]={5,6,7,8} st a[]={10,&s[0 # include # include int mian () { int m,n,i,s=0; int a[10000 void main() {union { int k; char i[2]; }*s,a; s=&a; s->i[0]= #include int f(int n); main() {int a=3,s; s=f(a);s=s+=(a);pr 若定义int s=3,a=5;则表达式s=2?a++:--a的值为 i=1;a=0;s=1; do{a=a+s*i;s=-s;i++;}while(i 若有定义int s[4]={1,2,3,4};则a[a[2]－3*a[0]+1]的值是