;while(1){b[l++]=n;if(n&1)n=1+n+(n >=1 ;if(n=1 ;if(n

if ((n!=0)&&(n IF语句不能执行for (n = 1; n < 100000;n++ )if ((totalSecond =a * 60 if ((n & -n) == n) (n+1)^n-(n-1)^n=? int fac(int n) {if(n==0||n==1) return 1; else return n*fac(n void p(int n) { if (n>1 &&n%2==1) p(n-1); printf(“%2d”,n); i double fact(int n) { if (n==0) return 1; else return n*(fact int n = 0; while (n++) { if (n>3) { break; } } 请问n结果是多少? s(n) { if(n=1) return 1; else return s(n-1)+n*n*n }和 for(i=1 if (n==0) return 0; else if (n==1) return int fun(static int n) {if(n==1)return 1; else return(n+fun(n if n is a positive integer and 2^n + 2^n+1=k,what is 2^n+2 i