弦长2.6米,弦到弧顶0.8米,求弧长?
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弦长2.6米,弦到弧顶0.8米,求弧长?
弦长L=2.6米,弦到弧顶H=0.8米,求弧长C?
弧半径为R,弧所对圆心角为A.
R^2=(R-H)^2+(L/2)^2
R^2=R^2-2*R*H+H^2+L^2/4
2*R*H=H^2+L^2/4
R=H/2+L^2/(8*H)
=0.8/2+2.6^2/(8*0.8)
=1.456米
A=2*ARC SIN((L/2)/R)
=2*ARC SIN((2.6/2)/1.456)
=126.43度
=126.43*PI/180
=2.2066弧度
C=A*R
=2.2066*1.456
=3.213米
弧半径为R,弧所对圆心角为A.
R^2=(R-H)^2+(L/2)^2
R^2=R^2-2*R*H+H^2+L^2/4
2*R*H=H^2+L^2/4
R=H/2+L^2/(8*H)
=0.8/2+2.6^2/(8*0.8)
=1.456米
A=2*ARC SIN((L/2)/R)
=2*ARC SIN((2.6/2)/1.456)
=126.43度
=126.43*PI/180
=2.2066弧度
C=A*R
=2.2066*1.456
=3.213米