x^2+y^2+z^2-2yz+2xz-2xy 可以化简吗
(2X+Z-Y)/(X^2-XY+XZ-YZ)-(Y-Z)/(X^2-XY-XZ+YZ)
求(2X+Z-Y)/(X^2-XY+XZ-YZ)-(2X+Y+Z)/(X^2+XY+XZ+YZ)
化简(2x-y-z/x^2-xy-xz+yz)+(2y-x-z/y^2-xy-yz+xz)+(2x-x-y/z^2-xz
一道初二分式计算题(2X+Z-Y)/(X^2-XY+XZ-YZ)-(2X+Y+Z)/(X^2+XY+XZ+YZ)
设x,y,z∈R+,xy+yz+xz=1,证明不等式:(xy)^2/z+(xz)^2/y+(yz)^2/x+6xyz≥x
x^2+y^2+xy=25/4,x^2+z^2+xz=169/4,y^2+z^2+yz=36,求xy+xz+yz
x^2+y^2+z^2=2,xy+yz+xz的范围
xy/x+y=1,yz/y+z=2,xz/x+z=3求x,y
2^x=5^y=10^z证明xy=xz+yz
2^x=5^y=10^z证明xy=xz=yz
因式分解x^2-xy+xz-yz
如果1=xy/x+y,2=yz/y+z,3=xz/x+z,则x的值?