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(96/y²16)+(3y-1/4-y)=(2y-1/y+4)-5

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(96/y²16)+(3y-1/4-y)=(2y-1/y+4)-5
(96/y²16)+(3y-1/4-y)=(2y-1/y+4)-5
你的题目应该是:(96/y²16)+(3y-1)/(4-y)=(2y-1)/(y+4)-5 对吗?
(96/y²16)+(3y-1)/(4-y)=(2y-1)/(y+4)-5
方程式左右都乘以y²16*(4-y)*(y+4),得到
96(4-y)(y+4)+16y²(3y-1)(y+4)=16y²(2y-1)(4-y)-5*16y²(4-y)(y+4)
化简后
-96y²+96*16+48y^4+176y^3-64y²=-32y^4+144y^3-64y^2+80y^4-1280y^2
32y^3+1184y^2+1536=0
y^3+37y^2+48=0
再问: 刚刚有个打错了是分式方程(96/y²-16)+(3y-1/4-y)=(2y-1/y+4)-5
再答: (96/y²-16)+(3y-1)/(4-y)=(2y-1)/(y+4)-5 方程式左右都乘以(y-4)*(y+4),得到 96-(3y-1)(y+4)=(2y-1)(y-4)-5(y-4)(y+4) 96-3y^2-11y+4=2y^2-9y+4-5y^2+80 2y=16 y=8