计算下列分式,1/(x-10)+1/x=1/121+1200/(x+100)=1200/x
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计算下列分式,
1/(x-10)+1/x=1/12
1+1200/(x+100)=1200/x
1/(x-10)+1/x=1/12
1+1200/(x+100)=1200/x
x/x(x-10)+(x-10)/x(x-10)=1/12
(2x-10)/x(x-10)=1/12
x(x-10)=12(2x-10)
x^2-10x=24x-120
x^2-34x+120=0
(x-30)(x-4)=0
x1=30,x2=4
[(x+100)+1200]/(x+100)=1200/x
1200(x+100)=x(x+1300)
x^2+6300x=1200x+120000
x^2+100x=120000
(x-300)(x+400)=0
x1=300,x2=-400
(2x-10)/x(x-10)=1/12
x(x-10)=12(2x-10)
x^2-10x=24x-120
x^2-34x+120=0
(x-30)(x-4)=0
x1=30,x2=4
[(x+100)+1200]/(x+100)=1200/x
1200(x+100)=x(x+1300)
x^2+6300x=1200x+120000
x^2+100x=120000
(x-300)(x+400)=0
x1=300,x2=-400
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