怎么证明log2 12=log1 12

解不等式log1/2^(x+1) +log2^[(1/(6-x)] 大于log1/2^12 对数换算问题y=log1/2^x=-log2^x怎么换的 对数运算题一道log2(12)+log1/2(3倍根号2）等于多少 log2[log1/2(log2x)]=log3[log1/3(log3y)]=0 比较XY的大小 1/2^(log2(12))怎么算? 已知x满足不等式log1/2（x^2）≥log1/2(3x-2),求函数f(x)=log2（x/4)*log2（x/2) 已知x满足不等式log1/2x^2≥log1/2(3x-2),求函数f(x)=(log2^x/4)*(log2^x/2) 已知x满足不等式2(log1/2 x)^2+7log1/2 x+3≤0.f(x)=(log2 x/4)^2(log2 x log2(根号下7/48)+log2(12)-1/2log2(42)-1=? 若2(log1/2x)2+7log1/2x+3小于等于0,求Y=log1/2(x/2).log2(x/4)的最大值与最小 若a=log2 3.b=log3 2,c=log1/3 2.d=log2 1/3 设a=log1/3 2 b=log2 3 c= 1/2 ^0.3