[0 1 2 3] [3 2 1 0] [-1 2 3 4]
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[0 1 2 3] [3 2 1 0] [-1 2 3 4]
A=[1 3 1 4] B= [2 -1 -1 1] C= [0 2 0 -1]
[2 0 3 1] [0 -1 3 2] [-1 1 3 1]
求(1)A+2B (2)A+B-C
A=[1 3 1 4] B= [2 -1 -1 1] C= [0 2 0 -1]
[2 0 3 1] [0 -1 3 2] [-1 1 3 1]
求(1)A+2B (2)A+B-C
/>(1)A+2B=1 3 1 4 + 2[2 -1 -1 1] =[5 1 -1 6 ]
2 0 3 1 [0 -1 3 2] [2 -2 9 5]
(2) A+B-C=[1 3 1 4 ] +[ 2 -1 -1 1] -[ 0 2 0 -1]
[ 2 0 3 1] [ 0 -1 3 2] [ -1 1 3 1]
=[3 2 0 5 ] -[ 0 2 0 -1 ]
[3 -1 6 3] [ -1 1 3 1 ]
=[ 3 0 0 6 ]
[ 4 -2 3 2]
2 0 3 1 [0 -1 3 2] [2 -2 9 5]
(2) A+B-C=[1 3 1 4 ] +[ 2 -1 -1 1] -[ 0 2 0 -1]
[ 2 0 3 1] [ 0 -1 3 2] [ -1 1 3 1]
=[3 2 0 5 ] -[ 0 2 0 -1 ]
[3 -1 6 3] [ -1 1 3 1 ]
=[ 3 0 0 6 ]
[ 4 -2 3 2]
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