cosθ^2+cos(θ+π/3)^2-cosθcos(θ+π/3)化简

cosθ^2+cos(θ+2π/3)^2+cos(θ-2π/3)^2 计算 θ∈(0,π/2),比较cosθ、sin(cosθ)、cos(sinθ)的大小 化简：根号下1-cos(2π+θ)/1+cos(2π+θ)+根号下1+cos(2π+θ)/1-cos(2π+θ)( π ①化简[sin(2π+α)*cos(7π-α)]/cos(-α)②已知cosθ=-3/5,θ∈(π/2,π),求sin( 化简：1+sinθ+cosθ+2sinθcosθ /1+sinθ+cosθ sin(π-θ）+cos(2π-θ）/cos(5π/2-θ)+sin(3π/2+θ)=2,则sinθcosθ=_____ 已知向量m=(cosθ,-sinθ),n=(根号2+sinθ,cosθ),θ∈(π,3π/2),且cos(θ/2+π/8 已知 sin(θ+kπ)=-2cos (θ+kπ) 求 ⑴4sinθ-2cosθ/5cosθ+3sinθ; ⑵(1/4) 三角函数化简[2cos^3θ+sin^2(π-θ)+sin(π/2+θ)-3]/[2+2cos^2(π+θ)+cos(- 求2sinθ+√3cosθsinφ-cosθcosφ的最大值和最小值 已知(4sinθ-2cosθ)/(3sinθ+5cosθ)=6/11,求5cos^2θ/(sin^2θ+2sinθcos 2cos³θ+sin²(360°-θ)+cos(360°-θ)-3/2+2cos²(180°-θ)+cos(-θ)怎样化