如图,AB=AC,AD=AE,角BAC=角DAE,证∠B=∠C
已知:如图∠DAE=∠BAC,AB=AC,∠B=∠C求证:AD=AE
如图,AB=AC,AD=AE,∠BAC=∠DAE=90°
已知,如图AB=AC,AD=AE,∠BAC=∠DAE
(1)如图,已知∠BAC=∠DAE,AB=AC,AD=AE,求证:∠B=∠C,BD=CE
如图,已知AB>AC,AD⊥BC,AE平分∠BAC,求证:∠DAE=1/2(∠C-∠B)
如图,AB=AC,AD=AE,∠BAC=∠DAE=α,求∠AOE.
已知:如图,AB=AC,AD=AE,BD=CE,求证:∠BAC=∠DAE
如图,已知AB=AC,AD=AE,BD=CE.试说明:∠BAC=∠DAE
已知:如图,AD=AE,AB=AC,∠DAE=∠BAC.求证:BD=CE.
已知:如图6-7,AD=AE,AB=AC,∠DAE=∠BAC.求证:BD=CE.
已知如图,AB=AC,AD=AE,角BAC=角DAE,试说明BC=CE
如图,AB=AC,AD=AE,BD=CE,求证角BAC=角DAE