(2-1)(2+1)(2^2+1)(2^4)...(2^64+1)+1=?
已知m=(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)(2^128
设M=(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1),试确定M-2
设M=(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)(2^128+
若A=(2+1)(2^2+1)(2^4+1)( 2^8+1)( 2^16+1)( 2^32+1)( 2^64+1) 求A
(2+1)(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1)=?
(2^2+1)(2^4+1)(2^8+1)(2^16+1)(2^32+1)(2^64+1),
1 1/2 1/8 1/64
求和:1/2+1/4+1/8+1/16+1/32+1/64+.+1/1024=?
1-2/1-4/1-8/1-16/1-32/1-64/1=多少?
1-2/1-4/1-8/1-16/1-32/1-64/1=?简便计算
1+2+1+2+1+2+1+2+1+2+1+2+1+2 =( )*( ) =()
(1+1/2)(1+1/2^2)(1+1/2^4)(1+1/2^8)+1/2^15=?