如果有有理数a,b满足a=2,b=1,求ab/1+（a+1）（b+1)/1+(a+2)(b+2)/1`````+(a+2

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如果有有理数a,b满足a=2,b=1,求ab/1+（a+1）（b+1)/1+(a+2)(b+2)/1`````+(a+2007)(b+2007）/1的值

因1/[(a+n)(b+n)]=(a-b)[1/(b+n)]-[1/(a+n)]=1/(b+n)]-[1/(a+n)],(n=0,1,2,3,...),故原式=[1+(1/2)+(1/3)+...+(1/2007)+(1/2008)]-[(1/2)+(1/3)+(1/4)+...+(1/2008)+(1/2009)]=1-(1/2009)=2008/2009.

如果有理数a,b满足|ab-2|+（1-b)平方如果有理数a,b满足|ab-2|+（1-b)的2次方=0 试求1/ab+1/(a+a)(b+1)+1(a+2)(b+2) 如果有理数a和b满足|ab-2|+|1-b|=0,试求1/ab+1/（a+1)(b+1)+1/(a+2)(b+2）+.. 已知有理数a,b满足|a+b-2|+(a^2*b^2+2ab+1)=0,求代数式:(a-2b+3)(a-2b-3)-(b 如果有理数a、b满足|ab-2|+|1-b|=0,试求1/ab+1/（a+1）（a+1）+1/(a+2)(a +2)+. 如果有理数a,b满足|ab-2|+|1-b|=0.试求1/ab+1/(a+1)(b+1)+1(a+2)(b+2)+…+1 如果有理数a,b满足|ab-2|+(1-b)^2=0,求1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)…+ 如果有理数a,b满足|ab-2|+(1-b)^2=0,试求1/ab+1/(a+1)(b+1)+1/(a+2)(b+2)… 如果有理数a,b满足|ab-2|+|1-b|=0,试求1 /ab+1/（a+1)(b+1)+1/(a+2)(b+2)+. 如果有理数a,b满足|ab-2|+(1-b)的二次方=0求1\ab+1\（a+1)(b+1)+1|（a+2)(b+2)+ 如果有理数啊,a,b满足|ab-2|+(1-b)的二次方=0,试求1/ab+1/(a+1)(b+1)+1/(a+2)(b 如果有理数a,b满足|ab-2|+(1-b)的平方=0,试求：ab分之1+（a+1）(b+2）分之1+.+（a+2007