已知数列an,若a1=1,nan+1=(n+2)Sn,求证Sn/n为等比数列
数列An的前n项和为Sn,已知A1=1,An+1=Sn*(n+2)/n,证明数列Sn/n是等比数列
已知数列{an}的前n项和为Sn,又a1=2,nAn+1=sn+n(n+1),求数列{an}的通项公式
设数列{an}的前n项和为sn,已知a1+2a2+3a3+…+nan=(n-1)Sn+2n(n∈N*)
设数列An的前n项和为Sn,已知a1=1,An+1=Sn+3n+1求证数列{An+3}是等比数列
已知数列{an}的前n项和伟Sn,且a1=1,na(n+1)=(n+2)Sn,n属于N* 求证数列{Sn/n}为等比数列
证明数列是等比数列数列前n项和为Sn,a1=1,a(n+1)=(n+2)Sn/n,求证Sn/n是等比数列,
已知数列an的前n项和为Sn,Sn=三分之一×【a1-1】求a1,a2 .求证数列an是等比数列
数列{an}的前n项和为Sn,已知a1=1,an+1=(n+2/n)Sn(n=1,2,3,…)求证{Sn/n}是等比数列
设数列{an}的前n项和为Sn,已知a1=1,Sn=nan-2(n-1)n
已知数列{an}的前n项和为Sn,并且满足a1=2,nan+1=Sn+n(n+1),
已知数列an的前n项和为Sn,a1=2,nan+1=Sn+n(n+1),
设数列an的前n项和为Sn 已知a1+2a2+3a3+……+nan=(n-1)Sn+2n