log2[log3[log5 125]]=?

化简log2[log3(log5 125)]…… (log2)和(log3)变成(log5) log2(a)=log3(b)=log5(c) 若log2(x)=log3(y)=log5(z) log2^25*log3^2倍根号2*log5^9= log2^5*log3^2倍根号2*log5^9= log2(2)+log5(1)-log1/3(1/27)+[3^log3(5)]^2+3^-log3(2)=? log2 25*log3 4 *log5 9 我是这样做的log2(3)*log3(5)*log5(49)*log7(64)=log2(3)*log3(5)*2log 计算log2 6-log2 3,lg5+lg2,log5 3+log5 1/3,log3 5-log3 15 log的计算 ：log2（20）-log4（25)= log3(2)×log2（5）×log5（3）=?log2[log (log3^4+log5^2)(log2^9+log2^根号3)