解线性方程组(1)2x+3y-5z=3 (2) x-2y+z=0 (3)3x+y+3z=7用矩阵变换法谢谢大神们

来源：学生作业帮编辑：神马作文网作业帮分类：数学作业时间：2024/11/19 01:07:13

/ 1 -2 1 0 \ / 1 -2 1 0 \ / 1 -2 1 0 \ / 1 -2 1 0 \
| 2 3 -5 3 |=> | 0 7 -7 3 |=> | 0 7 0 7 |=> | 0 7 0 7 |=>
\ 3 1 3 7 / \ 0 7 0 7 / \ 0 7 -7 3 / \ 0 0 -7 -4 /
/ 1 0 0 10/7 \
| 0 1 0 1 |=>x=10/7 y=1 z=4/7
\ 0 0 1 4/7 /

试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) {x+y+z=1;x+3y+7z=-1;z+5y+8z=-2 x/2=y/3=z/5 x+3y-z/x-3y+z 已知x,y,z 大于0,x+y+z=2,求证 xz/y(y+z)+zy/x(x+y)+yx/z(z+x)大于等于2/3 解三元一次方程：x+y-z=0,2x+y+z=7,x-3y+z=8 2x+5y+4z=0,3x+y-7z=0,则x+y-z=? 方程组用逆矩阵来解?x+2y+z=0;2x+9y+2z=0;3x+y+z=-2; 求用矩阵解三元方程x+y-z=3-z+y+2x=42y+z+2x-12=0suppose inverse of the 已知x+4y+3z=3x-2y-5z=0,求x+2y-z/2x-3y+7z的值 x-y-z=-1 3x+5y+7z=11 4x-y+2z=-1 分别求出x=?y=?z=? 解方程一;{x+y-z=6,x-3y+2z=1,3x+2y-z=-7.②{3x+4z=7,2x+3y+z=9,5x-9y {5x-3y+z=2{5x+2y-4z=3{-5x+y-z=2 {x-y-z=-1{3x+5y+7z{4x-y+2x=-