x+y+z=6 x+2y+3z=14 y+1=z
试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)
(x+y-z)(x-y+z)=
3x+2y+z=14 ,x+y+z=10,z+2x+3y=1 5
[3x+2y+z=14,x+y+z=10,2x+3y-z=1]
3x+2y+z=14 x+y+2z+-3 2x+3y-z=1
{x+y+z=1;x+3y+7z=-1;z+5y+8z=-2
如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0求x,y,
解方程组2x+y-3z=1,x-2y+z=6,3x-y+2z=9求x,y,z的值
x/2=y/3=z/5 x+3y-z/x-3y+z
已知x::y:z=3:4:5,(1)求x+y分之z的值;(2)若x+y+z=6,求x,y,z.
3道高数题,1,函数F(x,y,z)=(e^x) * y * (z^2) ,其中z=z(x,y)是由x+y+z+xyz=
如果,根号x-3+| y-2 |+z^2=2z-1 求 (x+z)^y