计算：2x^3y[(3xy^2)^2)+(-4xy^3)(-xy)] (ab^2)^3*(ab^2)^2

来源：学生作业帮编辑：神马作文网作业帮分类：数学作业时间：2024/11/06 05:42:25

计算：2x^3y*[(3xy^2)^2)+(-4xy^3)*(-xy)] (ab^2)^3*(ab^2)^2
(3.6*10^4)*(5*10^7)+(3*10^5)*(9*10^6)
(3x^2+1/2y-2/3y^2)*(-1/2xy)^3

2x^3y*[(3xy^2)^2)+(-4xy^3)*(-xy)]
=2x^3y*[9x^2y^4+4x^2y^]
=2x^3y*13x^2y^4
=26x^5y^5
(ab^2)^3*(ab^2)^2
=a^2b^6*a^2b^4
=a^4b^10
(3.6*10^4)*(5*10^7)+(3*10^5)*(9*10^6)
=18*10^11+27*10^11
=(18+27)*10^11
=45*10^11
=4.5*10^12
(3x^2+1/2y-2/3y^2)*(-1/2xy)^3
=(3x^2+1/2y-2/3y^2)*(-1/8x^3y^3)
=-3/8x^5y^3-1/16x^3y^4+1/12x^3y^5

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