已知AD是△ABC的中线AE⊥AB,AF⊥AC且AE=AB,AF=AC连接EF求证AD=1/2EF

AD是三角形ABC是的中线,AE垂直AB,AF垂直AC,且AE=AB,AF=AC,连接EF,求证:AD=2/1EF 如图,AD是三角形ABC的中线,AE垂直AC,AF垂直AB,且AE=AC,AF=AB,求证：AD=1/2EF AD是三角形abc的中线ae垂直ab,af垂直ac,ae等于ab,af等于ac,求证ef等于2ad.ef垂直ad 如图,AD∥BC,AD=BC,AE⊥AD,AF⊥AB,且AE=AD,AF=AB,求证：AC=EF. 如图,已知：AD是△ABC的中线,AE⊥AC,AF⊥AB,且AE＝AC,AF＝AB试判断AD与EF的关系,并说明理由 如图,已知AD//BC,AD=BC,AE⊥AD,AF⊥AB,AE=AD,AB=AF.求证：AC=EF. 如图,已知AE⊥AD,AF⊥AB,AF=AB,AE=AD=BC,AD∥BC,求证：（1）AC=EF（2）AC⊥EF 如图,已知AE⊥AD,AF⊥AB,AB//CD,AE=CD,AE=AD,AF=CD,求证AC=EF 如图,已知AE⊥AD,AF⊥AB,AF=AB,AE=AD=BC,AD‖BC,求证AC⊥EF 已知AE⊥AD,AF⊥AB,AE=AD=BC,AD‖BC,求证:⑴AC=EF⑵AC⊥EF 如图,已知AE⊥AD,AF⊥AB,AB∥CD,AF=CD,AE=AD,求证：AC垂直EF. 如图9,AD//BC,AE⊥AD且AE=AD,AF⊥AB且AF=AB.则AC与EF是否相等?为什么?