化简：1.根号下(1-sin^2)2.(1-cos^4x-sin^4x)/(1-cos^6x-sin^6x)

化简[1-(sin^4x-sin^2cos^2x+cos^4x)/(sin^2)]+3sin^2x 化简2sin^2[(π/4)+x]+根号3（sin^x-cos^x）-1 化简 1/2cos x-根号3/2sin x 根3sin x+cos x 根号下(sin""x+4cos"x)-根号下(cos""x+4sin"x)=? 三角等式求证：cos^6x+sin^6x=1-3sin^2x+3sin^4x (1-(sin^4x-sin^2xcos^2x+cos^4x)/sin^2x +3sin^2x 化简（1)√3sin x+cos x (2）√2(sin x-cos x) （3）√2cos x-√6sin x 求证（cos^2 x-sin^2 x)(cos^4 x+sin^4 x)+1/4 sin 2x sin 4x=cos 2 已知sin X+cos X=m,|m|小于等于根号2且|m|不等于1,求sin X^3+cos X^3,sin X^4+ 2cos x (sin x -cos x)+1 sin(1/x)-cos(1/x)/x 函数f(x)=负根号3sin ^2x+sin x cos x f(a/2)=1/4-根号3/2求sin a值