x+y+z=100 4x+3y+1/3=100 请问 怎么解
请问怎么由2x-3y+z=0 ,3x-2y-6z=0 得到x=3z,y=4z
100x+10y+z=48(x+Y+Z) x+Z=y+3 100x+10y+z-(100z+10y+x)=198 怎么解
(X+Y)Z=1 (1.2X+Y)9/10=1 (X+3/4Y)(Z+2.5)=1 方程组怎么解?只要求解出Z.
解方程一;{x+y-z=6,x-3y+2z=1,3x+2y-z=-7.②{3x+4z=7,2x+3y+z=9,5x-9y
解三元一次方程组,100x+10y+z=27(x+y+z) {x+y-z=1 (100z+10y+x)-(100x+10
已知5x+3y+1/3z=100 7x+y+z=100 那么x+y=?
x+y+z=22,3x+y=47,x=4z+2怎么解
x-2+z/9=2x+y+3z/10=-(3x+2y-4z)/(-3)=1,怎么解
解方程组1、4x+9y=12,3y-2z=1,2x+6z=32、3x-y+2z=3,2x+y-3z=11,x+y+z=1
解三元一次方程组 1.{2x-y+z=1,3x+y-2z=2,x+2y-z=3 2.{3x-y+z=4,2x+3y-z=
解三元一次方程组1、x+y-z=4 2x-y+z=5 x-3y+z=-2 2、y+2z=-2 3x+y-4z=1 2x-
解三元一次方程组 ①2x-y+z=1 3x+y -2z=2 X+2y-z=3 ②x-4y+z=-3 2x+Y-Z=18