作业帮 > 数学 > 作业

(1x3)/1+(3x5)/1+(5x7)/1+...+(99x101)=?

来源：学生作业帮 编辑：神马作文网作业帮 分类：数学作业 时间：2024/11/15 13:21:35
(1x3)/1+(3x5)/1+(5x7)/1+...+(99x101)=?
(1x3)/1+(3x5)/1+(5x7)/1+...+(99x101)=?
1/(1×3)=1/2×(1-1/3)
1/(3×5)=1/2×(1/3-1/5)
裂项法
所以原式=1/2×(1-1/3+1/3-1/5+……+1/99-1/101)=1/2×(1-1/101)=1/2×100/101=50/101
1/1x3+1/3x5+1/5x7+……+1/99x101 经典奥数题11/1x3+1/3x5+1/5x7.1/99x101解题思路请写清楚 2/1x3 + 2/3x5 + 2/5x7 +······+ 2/97x99 + 2/99x101 简便计算 1x1-2x2+3x3-4x4+5x5-6x6.-100x100+101x101 1/1X3+1/3X5+1/5X7...1/17X19+1/19X21= 1/1x3+1/3x5+1/5x7+1/7x9+1/9x11=? 1/1x3+1/3x5+1/5x7+.+1/2009x2011= 2/1x3+2/3X5+2/5x7=2/7x9+2/9x11 1/1x3+1/3x5+1/5x7.1/2009x2010+1/2011x2013 计算：1/1x3+1/3x5+1/5x7+...1/2009x2011+1/2011×2013 1/1x3+1/3x5+1/5x7+…+1/2011x2013是多少? 1/(1x3)+1/(3x5)+1/(5x7)+.+1/(2011x2013) 等于什么