X+y=10 2x+y=8 x = y=
【2(x-y)^3-8(x-y)^2(x+y)+6y(x-y)^2】/2(x-y)^2=
[x(x-y)-y(x-y)+(x+y)(x-y)]÷2x其中x=2012 y=2013
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai
已知2x-y=10,求[(x²+y²)-(x-y)²+2y(x-y)]/4y
已知X-Y/X+Y=3,求代数式2(x-y)/X+Y-3X+Y/X+Y
已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)
(x+2y)(x-2y)-(2y-x)(-2x-y)其中x=8,y=-8
[(x+2y)(x-2y)-(x-2y)^2+8y(x+y)]除以4x=
y'-2y=(e^x)-x
y'+2y/x=x通解
若x^2+y^2-8x-10y+41=0,求x/y+y/x的值
数学题已知p=x^/x-y-y^/x-y,q=(x+y)^-2Y(X+Y),