z=2x+y
xy/x+y=1,yz/y+z=2,xz/x+z=3求x,y
x=y/z=z/3,x+y+z =12,求2x+3y+4z是多少,
(y-x)/(x+z-2y)(x+y-2z)+(z-y)(x-y)/(x+y-2z)(y+z-2x)+(x-z)(y-z
解方程组:2X=3Y Y=2Z X+2Y+Z=16
x,y,z正整数 x>y>z证明 x^2x +y^2y+z^2z>x^(y+z)*y^(x+z)*z^(x+y)
解方程 (2x+y+z=15,x+2y+z=16,x+y+2z=17)
x-y-z=0 {x+y-3z=4 2x-5y+7z=21 三元一次方程解
若x/4=y/3=z/4,且x+y+z=12,求2x+3y+4z
已知x/2=y/3=z/5,且3x+4z-2y=40,求x、y、z的值﹔详解
已知方程组{2x-y+z=3,3x+4y-z=8,x+y-2z=-3,
解方程组:2x-y+z=6.-3x+2y-z=-9.x+y-2z=-1求解
已知有理数x,y,z,且|x-3|+2|y+1|+(2z+1)²=0,求x+y+z的相反数的倒数.