2001x(8/1-1/2009)+8x(1/2001-1/2009)-2009x(1/8+1/2009)+8 怎么用简

来源：学生作业帮编辑：神马作文网作业帮分类：数学作业时间：2024/11/20 03:14:39

2001x(8/1-1/2009)+8x(1/2001-1/2009)-2009x(1/8+1/2009)+8 怎么用简便方法计算

应该是2001x(1/8-1/2009)+8x(1/2001-1/2009)-2009x(1/8+1/2009)+8
=2001/8-2001/2009+8/2001-8/2009-2009/8-2009/2009+8
=（2001/8-2009/8）-（2001/2009+8/2009）+8/2001-1+8
=-1-1+8/2001-1+8=5又8/2001
再问：谢谢啦
再答：不客气

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