化简 [x^3(y^2-z^2)+y^3(z^2-x^2)+z^3(x^2-y^2)]/[x^3(y-z)+y^2(z-

来源：学生作业帮编辑：神马作文网作业帮分类：数学作业时间：2024/11/06 10:57:21

化简 [x^3(y^2-z^2)+y^3(z^2-x^2)+z^3(x^2-y^2)]/[x^3(y-z)+y^2(z-x)+z^3(x-y)]=
是y^3.
正确的是化简 [x^3(y^2-z^2)+y^3(z^2-x^2)+z^3(x^2-y^2)]/[x^3(y-z)+y^3(z-x)+z^3(x-y)]=

貌似分母的倒数第二项应该是y^3吧.
分子拆括号再提取公因式得(xy)^2(x-y)+(xz)^2(z-x)+(yz)^2(y-z)
分母拆括号再提取公因式得(xy)(x+y)(x-y)+(xz)(z+x)(z-x)+(yz)(y+z)(y-z)

试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) x/2=y/3=z/5 x+3y-z/x-3y+z 1.（x+y-z)+(x-y+z)-(x-y-z) 2.2x-(3x-2y+3)-(5y-2) (y-x)/(x+z-2y)(x+y-2z)+(z-y)(x-y)/(x+y-2z)(y+z-2x)+(x-z)(y-z 化简(y-x)(z-x)/(x-2y+z)(x+y-2z)+（z-y)(x-y)/(x-2z+y)(y+z-2x)+(x 因式分解：25x y^2 z^2 (x+y-z)-30xyz(z-x-y)^2+5x y z^3 (z-x-y) 已知x,y,z 大于0,x+y+z=2,求证 xz/y(y+z)+zy/x(x+y)+yx/z(z+x)大于等于2/3 x,y,z正整数 x>y>z证明 x^2x +y^2y+z^2z>x^(y+z)*y^(x+z)*z^(x+y) x=y/z=z/3,x+y+z ＝12,求2x+3y+4z是多少, 化简(y-x)(z-x)/(x-2y+z)(x+y-2z)+（z-y)(x-y)/(xy-2z)(y+z-2x)+(x- 如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0求x,y, {x+y+z=1;x+3y+7z=-1;z+5y+8z=-2