[log5(2)*log7(9)]/[log5(3)*log7(4)]

数学(log5 √2*log7 9)/(log5 1/3 *log7 3√4)+log2( √(3+√5)- log√( (log5根号2*log49 81)/(log25 1/3*log7 4开3次方）=? (log5根号2*log49^81)/(log25^(1/3)*log7^立方根4) 求值 3^2-log3(2)= log7(log5(log2(32)))=? log2(3)*log3(4)*log4(5)*log5(6)*log6(7)*log7(8)=? log2(3)+log3(4)+log4(5)+log5(6)+log6(7)+log7(8) （log5根号2底乘以log根号7底3 ）/log根号5底3分之1乘以log7底4的立方根 我是这样做的log2(3)*log3(5)*log5(49)*log7(64)=log2(3)*log3(5)*2log 若log3^5 log5^7 log7^x=log4^2 log6^4 log8^6,求x=? log5^6×log6^7×log7^8×log8^9×log9^10等于多少? log2为底3*log3为底4*log4为底5log5底6*log6底7*log7底8= log7(log5(log3|x|)))=0 能不能再详细一点,比如说log7怎么等于1还有log5怎么等于5的呢?