(1/2+1/3+...+1/2009)(1+1/2...+1/2008)-(1+1/2+...+1/2009)(1/2
来源:学生作业帮 编辑:神马作文网作业帮 分类:数学作业 时间:2024/11/11 23:22:38
(1/2+1/3+...+1/2009)(1+1/2...+1/2008)-(1+1/2+...+1/2009)(1/2+1/3+...+1/2008)
(1\2+1\3+...+1\2009)(1+1\2+...+1\2008) -(1+1\2+...+1\2009)(1\2+1\3+...+1\2008) =(1\2+1\3+...+1\2009)+(1\2+1\3+...+1\2009)(1\2+...+1\2008) -(1\2+1\3+...+1\2008)-(1\2+...+1\2009)(1\2+1\3+...+1\2008) =(1\2+1\3+...+1\2009) - (1\2+1\3+...+1\2008) = 1/2009
(1/2010-1)*(1/2009-1)*(1/2008-1)*...*(1/3-1)*(1/2-1)
|1/2011-1/2010|+|1/2011-1/2009|+|1/2009-1/2008|+...+|1/3-1/2
(-1*1/2)+(-1/2*1/3)+(-1/3*1/4)+.+(-1/2008*1/2009)+(-1/2009*1
|1/2-1|+|1/3-1/2|+1/4-1/3|+...|1/2009-1/2008|+|1/2010-1/2009
计算:|1/2-1|+|1/3-1/2|+|1/4-1/3|+...+|1/2009-1/2008|
1/2009-1/2008|+|1/2008-1/2007|+|1/2007-1/2006|+.+|1/3-1/2|+|
|2009/1-2008/1|+|2008/1-2007/1|+|2007/1-2006/1|+.+|3/1-2/1|+
(1/2010*1/2009*1/2008*...*1/3*1/2*1)^2011*(2010*2009*2008*..
(1-1/2)×(1-3/1)×.×(1-1/2008)×(1-1/2009)=?
计算:(2009/1-1)×(2008/1-1)×…×(3/1-1)×(2/1-1)等于多少?
(1/2+1/3.+1/2009)*(1+1/2+1/3..+1/2008)-(1+1/2+1/3..+1/2009)*
2009×(1+1/2+1/3+...+1/2008)-[1+(1+1/2)+ (1+1/2+1/3