请用累加法与累乘法1.数列an满足a1=1 an=an-1 +n 求通项公式2.数列anm满足an>0,a1=2,且an
数列的通项公式的求法1.累加法已知数列{an}满足an+1=an+2n+1,a1=1,求an2.累乘法已知数列{an}满
已知数列{An}满足An+1=2(n+1)*5的n次方*An,A1=3,用累乘法求数列{An}的通项公式
数列{an}满足a1=1,且an=an-1+3n-2,求an
设数列{an}满足an+1/an=n+2/n+1,且a1=2
已知数列an中满足a1=1且当n.=2时,2an*a*(n-1)+an-a(n-1)=0,求通项公式an
已知数列an满足an=1+2+...+n,且1/a1+1/a2+...+1/an
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数列{an}满足a1=1 an+1=2n+1an/an+2n
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已知数列{an}满足a1=1/2,sn=n^2an,求通项an
已知数列{an}满足,a1=2,a(n+1)=3根号an,求通项an