化简cos(α -π )tan(α-2π)tan(2π-α)/sin(π+α)

化简：[sin(π+α)*cos(π-α)*tan(π-α)]/[cos(π/2+α)*tan(3π/2-α)*tan( 求证:[sin^2(π+α)*cos(π/2-α)+tan(2π-α)*cos(-α)]/-sin^2(-α)+tan( 若α∈(0,π/6) 比较tan(sinα),tan(cosα),tan(tanα)的大小 化简sin³（﹣α）cos(2π+α）tan（2π-α)/sin(α-2π）cos(α-3π/2)-tan(π [sin(2π+α）·tan(-α)·cos(-α)]÷[sin(-α)·cos(2π+α）·tan(2π+α）化简 化简{sin(π+α)^3cos(-α)cos(π+α)}/{tan(π+α)^3cos(-π-α)^2} 化简cos(α-π)cot(5π-α)/tan(2π-α)sin(-2π-α) 计算sin(-α-5π)*cos(α-2分之π)-tan(α-2分之3π)*tan(2π-α) ①化简1+cos(π/2 +α)*sin(π/2 -α)*tan(π+α) 化简:(2cos^2α-1)/[2tan(π/4-α)sin^2(π/4+α)] 化简（2cosα-1)/(2tan(π/4-α)*sin(π/4+α)) 化简(2cos²α-1)/2tan(π/4+α)sin²(π/4-α)