初2因式分解计算题,通分约分

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初2因式分解计算题,通分约分
1题,3x平方+x分之9x平方-1乘9x平方-6x+1分之x平方-x
2题,x平方-6x+9分之x平方-2x-3乘x(x+1)分之x平方-x
3题,x平方-4x+4分之x平方-4除x平方-2x分之x平方+2x
4题,x平方-25分之x平方-4x-5除x平方+5x分之x平方+2x+1

1.
(9x^2-1)/(3x^2+x)*(x^2-x)/(9x^2-6x+1)
=[(3x+1)(3x-1)]/x(3x+1)*[x(x-1)/(3x-1)^2]
=(3x-1)/x*[x(x-1)/(3x-1)^2]
=(x-1)/(3x-1)
2.
(x^2-2x-3)/(x^2-6x+9)*(x^2-x)/x(x+1)
=[(x+1)(x-3)/(x-3)^2]*[x(x-1)/x(x+1)]
=[(x+1)/(x-3)]*[(x-1)/(x+1)]
=(x-1)/(x-3)
3.
(x^2-4)/(x^2-4x+4)除(x^2+2x)/(x^2-2x)
=(x^2-4)/(x^2-4x+4)*(x^2-2x)/(x^2+2x)
=[(x+2)(x-2)/(x-2)^2]*[x(x-2)/x(x+2)]
=[(x+2)/(x-2)]*[(x-2)/(x+2)]
=1
4.
(x^2-4x-5)/(x^2-25)除(x^2+2x+1)/(x^2+5x)
=(x^2-4x-5)/(x^2-25)*(x^2+5x)/(x^2+2x+1)
=[(x+1)(x-5)/(x-5)(x+5)]*[x(x+5)/(x+1)^2]
=[(x+1)/(x+5)]*[x(x+5)/(x+1)^2]
=x/(x+1)

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