2x+y=10① 4y+z=21② 5x-z=10③ y,z各为多少?
{5X+Y+Z①X+5Y+Z=-2②X+Y+5Z=10③
{2x+3y-4z=-5 x+y+z=6 x-y+3z=10
(4x-2y-z)-{5x[8y-2y-(x+y)]-x+(3y-10z)]=? kuai
若x、y、z、满足(9/8)^x ×(10/9)^y×(16/5)^z=2,则x、y、z、的值为多少
若4x=7y+5z,2x+y=z,则x:y:z的值为
(x+y-z)(x-y+z)=
若4x-3y-6z=0,x+2y-7z=0,求代数式5x*5x+2y*2y-z*z/2x*2x-3y*3y-10z*10
x,y,z为实数 且(y-z)^2+(x-y)^2+(z-x)^2=(y+z-2x)^2+(x+z-2y)^2+(x+y
x,y,z为实数且(y-z)平方+(x-y)平方+(z-x)平方=(y+z-2x)平方+(z+x-2y)平方+(x+y-
解三元一次方程组:(一)2x+y+z=4① x-y+3z=3 ②x+z=2③ 二;①2x+y+z=2 ②x+2y+z=5
1.x+y+z=30,3x+y-z=50,x,y,z为非负数,求5x+4y+2z取值范围.
已知3x-2y-5z=0,2x-5y+4z=0,且x,y,z均不为0,求3x*x+2y*y+5z*z/5x*x+y*y-