化简(-11/6 π)+cos(12/5 π)tan(4π)-1/(cos(13π/3))
化简(2cos^2A-1)/2tan(π/4-A)cos^2(π/4-A)
cosπ/3+tanπ/4+3tan²π/6+sinπ/2+cosπ+sin3π/2等于?.
1.求下列三角函数值:(1)tan(-11π/6);(2)cos(-π/6);(3)sin(-π/3);(4)cos(-
化简:[sin(π+α)*cos(π-α)*tan(π-α)]/[cos(π/2+α)*tan(3π/2-α)*tan(
tan(13π/3)+sin(-5π/2)+cos(-23π/6)
化简sin(3π-x)cos(x-3/2)cos(4π-x)/tan(x-5π)cos(π/2+x)sin(x-5/2π
计算cos(a+5π/12)cos(a+π/6)+cos(π/12-a)cos(π/3-a)
化简:(1)、tan(2π+α)tan(π+α)cos(-π-α)的3次方分之sin(-α)的平方乘以cos(π+α);
已知:tan(π+α)=-1/3,tan(α+β)=[sin2(π/2-α)+4(cosα)^2]/[10(cosα)^
知:tan(π+α)=-1/3,tan(α+β)=[sin2(π/2-α)+4(cosα)^2]/[10(cosα)^2
tan(a-4π)cos(π+a)sin^2(a+3π)/tan(3π+a)cos^2(2/5π+2)=0.5,求tan
化简{sin(π+α)^3cos(-α)cos(π+α)}/{tan(π+α)^3cos(-π-α)^2}