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请问一下几道数学题将2希函数化为顶点式,

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请问一下几道数学题将2希函数化为顶点式,
(1)y=x2+6x+10 (2)y=-2x2-5x+7
(3)y=3x2+2x (4)y=-3x2+6x-2
(5)y=100-5x2 (6)y=(x-2)(2x+1)
请问一下几道数学题将2希函数化为顶点式,
(1)y=x²+6x+10
=x²+6x+9+1
=(x+3)²+1
顶点(-3,1)
(2)y=-2x²-5x+7
=-2(x²+5/2x)+7
=-2(x²+5/2x+25/16-25/16)+7
=-2(x²+5/2x+25/16)+25/8+7
=-2(x+5/4)²+81/8
顶点(-5/4,81/8)
(3)y=3x2+2x
=3(x²+2/3x)
=3(x²+2/3x+1/9-1/9)
=3(x²+2/3x+1/9)-1/3
=3(x+1/3)²-1/3
顶点(-1/3,-1/3)
(4)y=-3x²+6x-2
=-3(x²-2x)-2
=-3(x²-2x+1-1)-2
=-3(x-1)²+1
顶点(1,1)
(5)y=100-5x2
=-5x²+100
顶点(0,100)
(6)y=(x-2)(2x+1)
=2x²-3x-2
=2(x²-3/2x)-2
=2(x²-3/2x+9/16-9/16)-2
=2(x²-3/2x+9/16)-25/8
=2(x-3/4)²-25/8
顶点(3/4,25/8)
以上全部,