求lim(x→0) (1-cos x) /x^2的极限
求lim(x→0)x cos 1/x lim(x→∞)x^2/ (3x-1)的极限
求lim(x→0+) ( 2/π*cosπ/2(1-x))/x的极限
求 lim(x→∞)[sin(2/x)+cos(1/x)]^x的极限.
求函数极限:lim(x->0) (cos x)^(1/x)
求函数极限lim x→0 e^x-x-1/x cos x
求函数的极限lim((x→x/2)cosx)/(cos(x/2)-sin(x/2))
求极限:lim(x→0)ln(1+x²)/ (sec x- cos x)
求极限:lim(1/sinx^2x-(cos^2x)/x^2) X趋于0
求极限lim(x→0)(x^3sin1/x)/(1-cos^2x),要详细过程~
求极限lim(x→0)(1-根号cosx)/[x(1-cos根号x)]
x趋于0,lim x^2 cos(1/x) 极限怎么求?
Lim[(3x)^1/2] * e^(cos(8pi/ x) ( x-->+0) 求极限?