数学问题(整式的加减)(11月21日21:30之前有效)
来源:学生作业帮 编辑:神马作文网作业帮 分类:数学作业 时间:2024/11/16 16:54:18
数学问题(整式的加减)(11月21日21:30之前有效)
一.化简
(1)a²-(ab-b²)-b²;
(2)(x²-y²)-3(2x²-3y²);
(3)7a²b-(-4a²b+5ab²)-2(2a²b-3ab²)
二.先去括号,再合并同类项
(1) (x-1)-(2x+1)
(2)3(x-2)+2(1-2x)
(3)2(2b-3a)+3(2a-3b)
(4)(3x²-xy-2y²)-2(x²+xy-2y²)
三.先化简,再求值:
(1)3x²+(2x²-3x)-(-x+5x²),其中x=314;
(2)(5xy-8x²)-(-12x²+4xy),其中x=-½,y=2
第一题的第一小题打错了
应该是:
a²-2(ab-b²)-b²
一.化简
(1)a²-(ab-b²)-b²;
(2)(x²-y²)-3(2x²-3y²);
(3)7a²b-(-4a²b+5ab²)-2(2a²b-3ab²)
二.先去括号,再合并同类项
(1) (x-1)-(2x+1)
(2)3(x-2)+2(1-2x)
(3)2(2b-3a)+3(2a-3b)
(4)(3x²-xy-2y²)-2(x²+xy-2y²)
三.先化简,再求值:
(1)3x²+(2x²-3x)-(-x+5x²),其中x=314;
(2)(5xy-8x²)-(-12x²+4xy),其中x=-½,y=2
第一题的第一小题打错了
应该是:
a²-2(ab-b²)-b²
一.化简
(1)a²-(ab-b²)-b²
=a²-ab+b²-b²
=a(a-b)
(2)(x²-y²)-3(2x²-3y²)
=x²-y²-6x²+9y²
=-5x²+8y²
=-(5x²-8y²)
(3)7a²b-(-4a²b+5ab²)-2(2a²b-3ab²)
=7a²b+4a²b-5ab²-4a²b+6ab²
=7a²b+ab²
=ab(7a+b)
二.先去括号,再合并同类项
(1) (x-1)-(2x+1)
=x-1-2x-1
=-x-2
=-(x+2)
(2)3(x-2)+2(1-2x)
=3x-6+2-4x
=-x-4
=-(x+4)
(3)2(2b-3a)+3(2a-3b)
=4b-6a+6a-9b
=-5b
(4)(3x²-xy-2y²)-2(x²+xy-2y²)
=3x²-xy-2y²-2x²-2xy+4y²
=x²-3xy+2y²
=(x-y)(x-2y)
三.先化简,再求值:
(1)3x²+(2x²-3x)-(-x+5x²)
=3x²+2x²-3x+x-5x²
=-2x
=-2×314
=-628
(2)(5xy-8x²)-(-12x²+4xy)
=5xy-8x²+12x²-4xy
=xy+4x²
=(-1/2)×2+4×(-1/2)²
=-1+1
=0
(1)a²-(ab-b²)-b²
=a²-ab+b²-b²
=a(a-b)
(2)(x²-y²)-3(2x²-3y²)
=x²-y²-6x²+9y²
=-5x²+8y²
=-(5x²-8y²)
(3)7a²b-(-4a²b+5ab²)-2(2a²b-3ab²)
=7a²b+4a²b-5ab²-4a²b+6ab²
=7a²b+ab²
=ab(7a+b)
二.先去括号,再合并同类项
(1) (x-1)-(2x+1)
=x-1-2x-1
=-x-2
=-(x+2)
(2)3(x-2)+2(1-2x)
=3x-6+2-4x
=-x-4
=-(x+4)
(3)2(2b-3a)+3(2a-3b)
=4b-6a+6a-9b
=-5b
(4)(3x²-xy-2y²)-2(x²+xy-2y²)
=3x²-xy-2y²-2x²-2xy+4y²
=x²-3xy+2y²
=(x-y)(x-2y)
三.先化简,再求值:
(1)3x²+(2x²-3x)-(-x+5x²)
=3x²+2x²-3x+x-5x²
=-2x
=-2×314
=-628
(2)(5xy-8x²)-(-12x²+4xy)
=5xy-8x²+12x²-4xy
=xy+4x²
=(-1/2)×2+4×(-1/2)²
=-1+1
=0