2X+2Y+Z=4 X+4Y+3Z=6 X+3Y+2Z=7

2x+5y+4z=6,3x+y-7z=-4,x+y-z=? 已知2x+5y+4z=6 3x+y-7z=-4求x+y-z 5x+3y+2z=2011 4x+6y+7z=2012 求x+y+z 已知有理数x、y、z满足条件|x-z-2|+(3x-6y-7)^2+|3y+3z-4|=0,求x、y、z 4x-3y-6z=0,x+2y-7z=0是一个方程组,那么x-y+z/x+y+z的值等于 x=y/z=z/3,x+y+z ＝12,求2x+3y+4z是多少, 试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y) 若4x-3y-6z=0,x+2y-7z=0,求代数式5x*5x+2y*2y-z*z/2x*2x-3y*3y-10z*10 1.x+y=16,y+z=12,z+x=102.3x-y+z=4,2x+3y-z=12,x+y+z=63.x+y+z=6 x+y+z=4 2x+3y-z=6 3x+2y+2z=10 x+2y+4z=17 2x+y+z=7 3x+y+2z=11 解方程：{2x+3y+z=7,x+y+z=4,3x+y-z=-4