素数和因式分解1.first show that a prime p cannot divide a product a
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素数和因式分解
1.first show that a prime p cannot divide a product a1b1 for natural numbers a1,b1
有英文的最好!
1.first show that a prime p cannot divide a product a1b1 for natural numbers a1,b1
有英文的最好!
这位兄台你是要大家给你翻译呢?还是给你求解.
我先给你翻译以下:
1.首先表明,p不能分开的产品a1,b1为自然数格A1中,B1 “假设磷划分a1b1 ,并表明磷也分为a1b2 ,在素B2 =剩余时,p是除以B1中,其中给出了一个无限的后裔.
2.现在使用上述1至推断的主要因子财产的显示,如果p分为AB公司,和p划分既不是也不b ,然后p划分的a1b1在格A1中,B1
我先给你翻译以下:
1.首先表明,p不能分开的产品a1,b1为自然数格A1中,B1 “假设磷划分a1b1 ,并表明磷也分为a1b2 ,在素B2 =剩余时,p是除以B1中,其中给出了一个无限的后裔.
2.现在使用上述1至推断的主要因子财产的显示,如果p分为AB公司,和p划分既不是也不b ,然后p划分的a1b1在格A1中,B1
英语翻译First,scatterplots show that this shift was systematic a
A divide B
divide A by
一个判断素数的函数#include int main(){\x09int prime(int a);\x09int a=
each of the following numbers as a product of prime factors是
a)Express 126 as the product of its prime factors in index n
That was quite a show!
that was a quiet show.
That was quit a show
if 7 is less than 4,then 7 is not a prime number(素数).
you cannot can a can that cannot be canned.
never can a can that cannot be