(a+b)^2+6-5a-5b

（3a+2b)(6a-5b)(2b-3a)(5a+6b) 若a,b满足|a+5b-2|+(a+b-6)²=0,求代数式（a-3b)(a+2b)-(a+5b)(a+3b) 已知a*a+b*b-2a+4b+5=0,求2(a+b)(a-b)+(a-b)(a-b)-(6a*a*b-2a*b*b)/ (3a-6b)/(a+b) - (5a-6b)/(a-b) - (4a-5b)/(a+b) - (7a-8b)/(a-b (3a-6b/a+b）-(5a-6b/a-b)-(4a-5b/a+b)-(7a-8b/b-a) 因式分解（a-b)-3a+3b (a+b)(a-b)-2b(3a-5b) [（a+2b)(a-2b)-(2a-b)²+(3a-b)(3a-5b)]÷2a 因式分解:(a+1)(a+3)(a+5)(a+7)+15 a(a-b+2)-6b(b+1) 8a+2b+5a-6b a(a-1)-(a×a-b)=-5,求(a×a+b×b)÷2-ab 解(5a+b)²-2(5a+b)(5a-b)+(5a-b)² 5(a+b)-3(a-b)=2 2(a+b)+5(a-b)=7