已知:AB=AD,AC=AE,∠BAD=∠CAE=90°BF=EF求证:AF⊥CD

来源：学生作业帮编辑：神马作文网作业帮分类：数学作业时间：2024/11/23 22:57:37

没有吐啊,F在哪猜不出来啊我猜出来图了简要说下2种方法
方法1取AB中点G,FG=AE/2=AC/2,AG=AB/2=AD/2,∠AGF=∠CAD（∠CAD+∠BAE=180,∠AGF+∠BAE=180）∠GAF=∠ADC∵∠GAF+DAF=90,∴∠ADC+∠DAF=90,即AF⊥CD
方法2倍长AF至A`,AFB全等A`FE,A`E=AB=DA,AE=CA,∠A`EA=180-∠BAE=∠DAC,△A`EA全等△DAC,∠AA`E=∠CDA,∠BAA`=∠CDA
角BAA`+∠FAD=90,∠CDA+∠FAD=90

如图,已知AE⊥AD,AF⊥AB,AB//CD,AE=CD,AE=AD,AF=CD,求证AC=EF 如图,已知AE⊥AD,AF⊥AB,AB∥CD,AF=CD,AE=AD,求证：AC垂直EF. AB=AD,AC=AE,BC=DE.求证∠BAD=∠CAE 如图,AB/AD=BC/DE=AC/AE,求证：∠BAD=∠CAE 已知：如图,AB=AD,AC=AE,∠BAD=∠CAE,求证：BC=DE 已知:如图,AB=AD,AC=AE,∠CAE=∠BAD.求证△EAD≌△CAB 已知:如图,AB/AD=BC/DE=AC/AE,求证:∠BAD=∠CAE 急已知AB⊥AC,AD⊥AE,AB=AC,AD=AE.求证1)△BAD≌△CAE 2)BD⊥CE 如图,已知AD//BC,AD=BC,AE⊥AD,AF⊥AB,AE=AD,AB=AF.求证：AC=EF. AB=AC,AD=AE,DE=BC,且∠BAD=∠CAE,求证:四边形BCDE是矩形如图,AB平行AC,∠BAD=∠CAE,AD=AE,求证：△ABE≌△ACD.(SAS) 如图,AB平行AC,∠BAD=∠CAE,AD=AE,求证：△ABE≌△ACD.