数列{an}中,a1=8,a4=2且满足an+2=2an+1-an(n∈N*)
数列{an}中,a1=8,a4=2且满足an+2=2an+1-an( n∈N*)
已知数列{an}中,a1=8,a4=2,且满足an+2-2an+1+an=0 (n∈N),求数列{an}的通项公式;设S
已知数列{an}中,a1=8,a4=2,且满足an+2-2an+1+an=0 (n∈N),求数列{an}的通项公式
数列{an}满足a1=1,且an=an-1+3n-2,求an
已知数列{an}满足:a1=1,且an-an-1=2n,求(1)a2,a3,a4.(2)求数列{an}的通项an
已知数列(an)满足a1=1,an+1=2an/an+2(n∈N*) 求a2,a3,a4,a5 猜想数列(an)的通项公
设数列{an}满足an+1/an=n+2/n+1,且a1=2
已知数列{an}满足:a1=1,且an-a(n-1)=2n.求a2,a3,a4.求数列{an}通项an
数列{an}}中,a1=8,a4=2且满足an+2=2an+1+an,n属于N,(1)求数列{an}的通项公式;(2)设
数列{an}满足a1=1 an+1=2n+1an/an+2n
已知数列an满足an=1+2+...+n,且1/a1+1/a2+...+1/an
在数列an中,a1=1,且满足a(n+1)=3an +2n,求an