(1+m^2-n^2/2n^2)÷(1+m-n/2n)的化简结果?
[(m+n)(m-n)-(m-n)²+2n(m-n)]÷4n
因式分解m^2-(n+1)m+n
m-n+2n^2/(m+n)
(m-n)^2 +n(n- m)
(m-n)+2n(m-n)
(m+n)(m-n)-(1-2n)化简
先化简再求值[(m+n)(m-n)-(m-n)²]÷(2n),其中m=-2,n=-1/2
m(m+n)(m-n)-m(m+n)的平方,其中m+n=1,mn=-1/2
3m(m-n)-2n(m-n)的平方
已知m-2n=3.求[(3m+2n)(3m-2n)-(m+2n)(5m-2n)]÷1/3 m 的值.
计算1/(m-n)-1/(m+n)-2n/(m^2+n^2)-4n^3/(m^4+n^4)-8n^7/(m^8+n^8)
先化简,在求值(m+n)(m-n)(-m^2-n^2)-(-2m+n)(-2m-n)(4m^2+n^2) 其中m=1,n