神马作文网三,第六页,
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三,第六页,
第三题
(1) N2(g) + 3H2(g) = 2NH3(g) ΔH= -92.2KJ/mol
(2) N2(g) + 2O2(g) = 2NO2(g) ΔH= +68KJ/mol
(3) 2Cu(s) + O2(g) = 2CuO(s) ΔH = -314KJ/mol
(4) C(s) + H2O(g) = CO(g) + H2(g) ΔH =+131.5KJ/mol
(5) N2H4(l) + O2(g) = N2(g) + 2H2O(l) ΔH = -622KJ/mol
(6) 2C8H18(l) + 25O2(g) = 16CO2(g) + 18H2O(l) ΔH = -11036KJ/mol
第四题
CO(g) + H2O(g) = CO2(g) + H2(g) ΔH = -41KJ/mol
CO2(g) + H2(g) = CO(g) + H2O(g) ΔH = +41KJ/mol
再问： 太给力了，你的回答完美解决了我的问题！
(1) N2(g) + 3H2(g) = 2NH3(g) ΔH= -92.2KJ/mol
(2) N2(g) + 2O2(g) = 2NO2(g) ΔH= +68KJ/mol
(3) 2Cu(s) + O2(g) = 2CuO(s) ΔH = -314KJ/mol
(4) C(s) + H2O(g) = CO(g) + H2(g) ΔH =+131.5KJ/mol
(5) N2H4(l) + O2(g) = N2(g) + 2H2O(l) ΔH = -622KJ/mol
(6) 2C8H18(l) + 25O2(g) = 16CO2(g) + 18H2O(l) ΔH = -11036KJ/mol
第四题
CO(g) + H2O(g) = CO2(g) + H2(g) ΔH = -41KJ/mol
CO2(g) + H2(g) = CO(g) + H2O(g) ΔH = +41KJ/mol
再问： 太给力了，你的回答完美解决了我的问题！