第一题 n=0s=0DOn=n+1s=s+ n的平方LOOP UNTIL s大于100PRINT nEND
Dim n% n = 1 Do Until n > 6 Print n; n = n + 2.4 Loop
阅读程序,结果是______ n=0 do n=n+1 debug.print n loop until n>2
vb题 s=0:n=5 for i=1 to n s=s+i next i print s;i 结果怎么是15
读程序,i=1S=0DOS=S+ii=i+2LOOP UNTIL i>20PRINT SEND(1)该程序是计算和式:_
s(n) = s(n-1)+(n-1);
int fun(char *s) { n=*s-'0';s++; while(*s!=0) {n=n*8+*s-'0';
n=6 Do Print n n=n+1 Loop while n
S=0 i=1 sum=0 DO s=s+i i=i+1 sum=sum+s LOOP UNTIL i≥100 PRIN
main() { int n,s; n=1; s=0; for(;n
cost[N-1][s]=0.5*s+(3+p[N-1][s])*(p[N-1][s]>0);这里的逻辑表达式的具体用法
VFP中CLEAR S=0 FOR n=1 TO 10 S=S+n n=n+1 ENDFOR S
C语言题 计算s=1+2+3+..….+n,直到s的值大于1000为止,输出s和n的值