用双十字相乘法分解因式: (1)x2-8xy+15y2+2x-4y-3; (2)x2-xy+2x+y-3;
来源:学生作业帮 编辑:神马作文网作业帮 分类:数学作业 时间:2024/11/12 14:16:57
用双十字相乘法分解因式: (1)x2-8xy+15y2+2x-4y-3; (2)x2-xy+2x+y-3;
x2-8xy+15y2+2x-4y-3;
=(x-3y)(x-5y)+2x-4y-3
x-3y -1
x-5y 3
x2-8xy+15y2+2x-4y-3=(x-3y-1)(x-5y+3)
(2)x2-xy+2x+y-3
=(x+2y)(x-y)+2x+y-3
x+2y 3
x-y -1
x2-xy+2x+y-3=(x+2y+3)(x-y-1)
再问: 两道题双十字相乘法的图
再答: x2-8xy+15y2+2x-4y-3; 1 -3 1 -5 =(x-3y)(x-5y)+2x-4y-3 x-3y -1 x-5y 3 x2-8xy+15y2+2x-4y-3=(x-3y-1)(x-5y+3) (2)x2-xy+2x+y-3 1 2 1 -1 =(x+2y)(x-y)+2x+y-3 x+2y 3 x-y -1 x2-xy+2x+y-3=(x+2y+3)(x-y-1)
=(x-3y)(x-5y)+2x-4y-3
x-3y -1
x-5y 3
x2-8xy+15y2+2x-4y-3=(x-3y-1)(x-5y+3)
(2)x2-xy+2x+y-3
=(x+2y)(x-y)+2x+y-3
x+2y 3
x-y -1
x2-xy+2x+y-3=(x+2y+3)(x-y-1)
再问: 两道题双十字相乘法的图
再答: x2-8xy+15y2+2x-4y-3; 1 -3 1 -5 =(x-3y)(x-5y)+2x-4y-3 x-3y -1 x-5y 3 x2-8xy+15y2+2x-4y-3=(x-3y-1)(x-5y+3) (2)x2-xy+2x+y-3 1 2 1 -1 =(x+2y)(x-y)+2x+y-3 x+2y 3 x-y -1 x2-xy+2x+y-3=(x+2y+3)(x-y-1)
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