#define N 2 #define M N+1 #define NUM (M+1)*M/2 main() {int
在C语言中为什么执行过 #define N 2 #define M N+1 #define NUM (M+1)*M/2以
define M 5#define N M+M main(){int k;k=N*N*5; printf("%d",k)
#define ADC_CHSEL_RES(n,m) _SBF(4*n,m) #define ADC_INT_ENABL
#include #define M 20; void main() { int i,j,k,p,t,n=0; int
#define N 5 #define f(M) ((N+1)*M) 求x=2*(N+1)+2*f(N+1); 求x的值
、 #define M(x,y,z) x*y+z main() { int a=1,b=2,c=3; printf("%
#define N 10 main() { int a[N]={1,2,3,4,5,6,7,8,9,10} int i,
帮我分析下这个题目#define ADD(x) x+xmain(){int m=1,n=2,k=3;int sum=AD
#define N 20 fun(int a[],int n,int m) {int i; for(i=m;i>n;i-
#define N 20 fun(int a[],int n,int m) { int i; for(i=m;i>=n;
#define Tap(X) 2*X+1 main() {int a=6,k=2,m=1; a+=Tap(k+m); p
#define SQR(X) X*X main() { int a=16,k=2,m=1; a/=SQR(k+m)/SQ