先化简再求值:(2a-2b/a²-2ab+b² + b/a²-b²)÷3b+2a
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先化简再求值:(2a-2b/a²-2ab+b² + b/a²-b²)÷3b+2a/a-b
其中a=5,b=2
其中a=5,b=2
(2a-2b/a²-2ab+b² + b/a²-b²)÷3b+2a/a-b
=[2(a-b)/(a-b)² + b/(a+b)(a-b)]×(a-b)/(3b+2a)
=[2/(a-b)+b/(a+b)(a-b)]×(a-b)/(3b+2a)
=[2(a+b)/(a+b)(a-b)+b/(a+b)(a-b)]×(a-b)/(3b+2a)
=[(3a+2b)/(a+b)(a-b)]×(a-b)/(3b+2a)
=1/(a+b)
=[2(a-b)/(a-b)² + b/(a+b)(a-b)]×(a-b)/(3b+2a)
=[2/(a-b)+b/(a+b)(a-b)]×(a-b)/(3b+2a)
=[2(a+b)/(a+b)(a-b)+b/(a+b)(a-b)]×(a-b)/(3b+2a)
=[(3a+2b)/(a+b)(a-b)]×(a-b)/(3b+2a)
=1/(a+b)
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