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先化简再求值:(2a-2b/a²-2ab+b² + b/a²-b²)÷3b+2a

来源:学生作业帮 编辑:神马作文网作业帮 分类:数学作业 时间:2024/11/17 09:26:39
先化简再求值:(2a-2b/a²-2ab+b² + b/a²-b²)÷3b+2a/a-b
其中a=5,b=2
先化简再求值:(2a-2b/a²-2ab+b² + b/a²-b²)÷3b+2a
(2a-2b/a²-2ab+b² + b/a²-b²)÷3b+2a/a-b
=[2(a-b)/(a-b)² + b/(a+b)(a-b)]×(a-b)/(3b+2a)
=[2/(a-b)+b/(a+b)(a-b)]×(a-b)/(3b+2a)
=[2(a+b)/(a+b)(a-b)+b/(a+b)(a-b)]×(a-b)/(3b+2a)
=[(3a+2b)/(a+b)(a-b)]×(a-b)/(3b+2a)
=1/(a+b)